1. The length of the side of a square is
represented by x+2. The length of the side of an equilateral triangle is 2x. If
the square and the equilateral triangle have equal perimeter, then the value of
x is _______.
Answer:
x
= 4
Explanation:
Since the side
of the square is x + 2, its perimeter = 4 (x + 2) = 4x + 8
Since the side
of the equilateral triangle is 2x, its perimeter = 3 * 2x = 6x
Also, the
perimeters of both are equal.
(i.e.) 4x + 8 = 6x
(i.e.) 2x = 8 è x = 4.
2. It takes Mr. Karthik y hours to
complete typing a manuscript. After 2 hours, he was called away. What
fractional part of the assignment was left incomplete?
Answer:
(y – 2) / y.
Explanation:
To type a manuscript karthik
took y hours.
Therefore his speed in
typing = 1/y.
He was called away after 2 hours
of typing.
Therefore the work completed =
1/y * 2.
Therefore the remaining work to
be completed = 1 – 2/y.
(i.e.) work to be completed = (y-2)/y
3. Which of the following is larger than
3/5?
(1) ½
(2) 39/50
(3) 7/25
(4) 3/10
(5) 59/100
(1) ½
(2) 39/50
(3) 7/25
(4) 3/10
(5) 59/100
Answer:
(2)
4. The number that does not have a
reciprocal is ____________.
Answer:
1
Explanation:
One
is the only number exists without reciprocal because the reciprocal of one is
one itself.
5. There
are 3 persons Sudhir, Arvind, and Gauri. Sudhir lent cars to Arvind and Gauri
as many as they had already. After some time Arvind gave as many cars to Sudhir
and Gauri as many as they have. After sometime Gauri did the same thing. At the
end of this transaction each one of them had 24. Find the cars each originally
had.
Answer:
Sudhir
had 39 cars, Arvind had 21 cars and Gauri had 12 cars.
6. A man bought a horse and a cart. If he
sold the horse at 10 % loss and the cart at 20 % gain, he would not lose
anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would
lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the
horse and Rs.________ for the cart.
Answer:
Cost
price of horse: Rs. 400 &
Cost
price of cart: Rs. 200
Explanation:
Let
x be the cost of horse & y be the cost of the cart.
10
% of loss in selling horse = 20 % of gain in selling the cart
Therefore (10 / 100) * x = (20 * 100) * y
è
x = 2y -----------(1)
5 % of loss in
selling the horse is 10 more than the 5 % gain in selling the cart.
Therefore (5 / 100) * x - 10 = (5 / 100) * y
è 5x - 1000 = 5y
Substituting (1)
10y
- 1000 = 5y
5y
= 1000
y
= 200
x
= 400 from (1) 
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